# Line slope calculator 6x-4y=-10

**Straight line given by points A[1; 4] and B[5; 10]**

## Calculation:

**Slope-intercept form of line:**y = 1.5x+2.5

**Canonical form of the line equation:**6x-4y+10 = 0

**Parametric form of the line equation:**

x = 4t+1

y = 6t+4 ; t ∈ R

**Slope:**m = 1.5

**Slope angle of line: φ =**56°18'36″ = 0.9828 rad

**X intercept:**x

_{0}= -1.6667

**Y intercept:**y

_{0}= q = 2.5

**Distance line from the origin:**d

_{0}= 1.3868

**The length of the segment AB: |AB| =**7.2111

**Vector: AB =**(4; 6)

**Normal vector: n =**(6; -4)

**Midpoint of the segment AB: M =**[3; 7]

**Perpendicular Bisector equation:**4x+6y-54 = 0

**Vector OA = (1; 4) ; |OA| = 4.1231**

**Vector OB = (5; 10) ; |OB| = 11.1803**

**Scalar product OA .OB = 45**

**Angle ∠ AOB = 12°31'44″ = 0.2187 rad**