# Line slope calculator 4x+5y=58

**Straight line given by points A[2; 10] and B[7; 6]**

## Calculation:

**Slope-intercept form of line:**y = -0.8x+11.6

**Canonical form of the line equation:**4x+5y-58 = 0

**Parametric form of the line equation:**

x = 5t+2

y = -4t+10 ; t ∈ R

**Slope:**m = -0.8

**Slope angle of line: φ =**-38°39'35″ = -0.6747 rad

**X intercept:**x

_{0}= 14.5

**Y intercept:**y

_{0}= q = 11.6

**Distance line from the origin:**d

_{0}= 9.0581

**The length of the segment AB: |AB| =**6.4031

**Vector: AB =**(5; -4)

**Normal vector: n =**(4; 5)

**Midpoint of the segment AB: M =**[4.5; 8]

**Perpendicular Bisector equation:**5x-4y+9.5 = 0

**Vector OA = (2; 10) ; |OA| = 10.198**

**Vector OB = (7; 6) ; |OB| = 9.2195**

**Scalar product OA .OB = 74**

**Angle ∠ AOB = 38°5'20″ = 0.6648 rad**