# Line slope calculator 2x+6y=62

**Straight line given by points A[1; 10] and B[7; 8]**

## Calculation:

**Slope-intercept form of line:**y = -0.3333x+10.3333

**Canonical form of the line equation:**2x+6y-62 = 0

**Parametric form of the line equation:**

x = 6t+1

y = -2t+10 ; t ∈ R

**Slope:**m = -0.3333

**Slope angle of line: φ =**-18°26'6″ = -0.3218 rad

**X intercept:**x

_{0}= 31

**Y intercept:**y

_{0}= q = 10.3333

**Distance line from the origin:**d

_{0}= 9.8031

**The length of the segment AB: |AB| =**6.3246

**Vector: AB =**(6; -2)

**Normal vector: n =**(2; 6)

**Midpoint of the segment AB: M =**[4; 9]

**Perpendicular Bisector equation:**6x-2y-6 = 0

**Vector OA = (1; 10) ; |OA| = 10.0499**

**Vector OB = (7; 8) ; |OB| = 10.6301**

**Scalar product OA .OB = 87**

**Angle ∠ AOB = 35°28'31″ = 0.6192 rad**